P V = n R T
so
n = PV / RT
T = 25 +273 = 298 degrees Kelvin
P= 1 atm = 1.013*10^5 Pascals
V = 0.350 Liters
R = 8.315 J/mol deg K
so
n = 1.013 * 10^5 * 0.350 / ( 8.315 * 298) = 14.3 mol
A sample of gas exhibits ideal behavior and occupies a volume of 350 mL at 25.0 C and 1.00atm. How many moles of gas are present in the sample?
2 answers
sorry, V should be in meters^3 with that R value
and we can use1 atm if we use
R = 0.08206 L atm / mol*deg K
n = 1 atm * 0.350 Liters / 0.08206*298 = 0.0143 mols
and we can use1 atm if we use
R = 0.08206 L atm / mol*deg K
n = 1 atm * 0.350 Liters / 0.08206*298 = 0.0143 mols