A sample of gas at 57C and 1.02atm occupies a volume of 2.20L. What volume would this gas occupy at 107C and 0.789atm?

Answer 1

T1 = 57 + 273
T2 = 107 + 273

P1 V1/T1 = P2 V2/T1

Answer 2

P1 V1/T1 = P2 V2/T2

Answer 3

1.02atm x 2,20L = 078atm x V2
330K 380K

2.244/ 330=.0068?

I'm lost.

Answer 4

T1 = 330
T2 = 380

1.02 * 2.2 / 330 = .789 * V2 /380

V2 = (1.02/.789)(380/330)(2.2)

= 3.28 L

Answer 5

note
expands as pressure goes down and expands as temperature goes up

so you can check if you have those ratios right.

Answer 6

Thanks!

Answer 7

You are welcome.