A sample of diborane gas (B2H6) , a substance that burst into the flame when expose to air has pressure of 345 toor at the negative 15 degree Celsius and a volume of 3.48L . New temperature is 36 degrees Celsius and the pressure is 468 toor, what will be the volume of the sample?

Answer 1

Using the combined gas law formula:

(P1)(V1) / (T1) = (P2)(V2) / (T2)

Where:
P1 = 345 torr
V1 = 3.48 L
T1 = -15°C + 273 = 258 K
P2 = 468 torr
T2 = 36°C + 273 = 309 K
V2 = unknown

Plugging in the values:

(345)(3.48) / 258 = (468)(V2) / 309

1123.3 / 258 = 468V2 / 309

V2 = (1123.3 * 309) / (258 * 468)
V2 ≈ 4.28 L

Therefore, the volume of the sample at the new temperature and pressure would be approximately 4.28 L.