According to Boyle's Law
P1V1=P2V2
P1 = 125 kPa P2 = ?
V1 = 3.50 L V2 = 2.00
P2=P1V1/V2
=125*3.50/2
P2=219kPa
A sample of CO2 occupies a volume of 3.50l at 125 kPa pressure,What pressure would the gas exert if the volume was decreased to 2.00l?
1 answer
1 answer