A sample of cesium metal reacted completely with water, evolving 48.7 mL of dry H2 at 24°C and 774 mmHg. What is the equation for the reaction? (Include states-of-matter under SATP conditions in your answer. Use the lowest possible coefficients.)

What was the mass of cesium in the sample?

1 answer

2Cs + 2H2O ==> H2 + 2CsOH
You will need to add the states depending upon the definitions given for SATP conditions.
Use PV = nRT and solve for n = number of moles. Using the coefficients in the balanced equation, convert moles H2 to moles Cs. Finally, using moles = grams/molar mass, convert moles Cs to grams Cs.