CaF2 molar mass = 78.07 check
Ca molar mass = 40.1
F2 molar mass = 2*19 = 38
8.4 g calcium is 8.4/40.1 = .2095 mol
.2095 mol of CaF2 = 16.35 grams, not 15 grams
now part a
30 g * 40.1/78.07 = 15.3
A sample of calcium fluoride with a mass of 15.0 g contains 8.40 g of calcium. Assuming that the sample is pure calcium fluoride, how much calcium would be present in a 30.0 g sample?
My answer: 16.8 g Ca
Based on your answer and applying what you know about calcium fluoride, is the 15.0 g sample actually pure calcium fluoride? Explain why or why not. Start with a molecular mass calculation to support your answer.
My molecular mass calculation:
mass of CaF2= (40.08)+(2)(19)= 78.08 g CaF2
I don't know where to go from here.
1 answer
1 answer