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A sample of aluminum increases its temperature from 20.1oC to 162.5oC by

absorbing 2175 J of heat. What is the mass of the aluminum sample?
(cAl = 0.900 J/goC)

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q = mass Al x specific heat Al x (Tfinal-Tinitial)
2175 = mass Al x 0.900 x (162.5 - 20.1)

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