Asked by Francis

A sample of a curium isotope was roasted. It was determined that the product( curium oxide) contained 11,59% of oxygen.¿ What is the equivalent weight of the isotope in the oxide? ¿ What is the mass of the curium isotope?
I have already gotten the answer for the first question ( equivalent weight = 61) but I don't know how to do the last question.
My teacher told me that the answer has to be 244g ,and I have to use the equivalent weight that I found but I really don't get how...
Could anyone tell how to calculate the mass of the isotope using the equivalent weight?
Answered by DrBob222

61 x 4 = 244.
Answered by Francis
Mmm how did you get the 4?
Answered by DrBob222
How did you get 61?
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