95% = mean ± 1.96 SEm
99% = mean ± 2.575 SEm
SEm = SD/√n
SD^2 = variance
I'll let you do the calculations.
A sample of 51 night-school students' ages is obtained in order to estimate the mean age of night-school students. x = 26 years. The population variance is 19.
(a) Give a point estimate for μ. (Give your answer correct to one decimal place.)
(b) Find the 95% confidence interval for μ. (Give your answer correct to two decimal places.)
Lower Limit
Upper Limit
(c) Find the 99% confidence interval for μ. (Give your answer correct to two decimal places.)
Lower Limit
Upper Limit
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