A sample of 10.0 grams of carbon dioxide gas is contained in a tank with a volume of 6.0 L so that the pressure inside the tank is 1.00 atm. What is the temperature of the gas sample?

Answer 1

To find the temperature of the gas sample, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure (1.00 atm)
V = volume (6.0 L)
n = number of moles (not given)
R = ideal gas constant (0.0821 L⋅atm/mol⋅K)

First, we need to calculate the number of moles of carbon dioxide gas in the sample. We can do this using the molar mass of carbon dioxide:

Carbon: 12.01 g/mol
Oxygen: 16.00 g/mol
Total molar mass of CO2 = 12.01 + 2(16.00) = 44.01 g/mol

Number of moles = mass/molar mass
Number of moles = 10.0 g / 44.01 g/mol = 0.227 moles

Now we can substitute the values into the ideal gas law equation and solve for temperature:

(1.00 atm)(6.0 L) = (0.227 moles)(0.0821 L⋅atm/mol⋅K)T

6.00 atm⋅L = 0.0227 T

T = 6.00 atm⋅L / 0.0227
T = 264.32 K

Therefore, the temperature of the gas sample is 264.32 K.