You can probably do a two-sample t-test on your data.
Using a stat calculator, I have the following:
t= -2.78
degrees of freedom = 5
Group A: Number of items= 6
28.0 31.0 42.0 48.0 50.0 53.0
Group B: Number of items= 6
29.0 30.0 45.0 55.0 56.0 58.0
Testing at .05 level of significance using a t-table, you will likely reject the null and conclude a difference in sales.
Check this result with your own calculations.
I hope this will help.
a sales manager wants to know whether a special promotional campaign is a success. he had the following data-Retail outlets :1 2 3 4 5 6 ; Sales before campaign : 50 48 31 42 28 53 ; Sales after campaign : 56 55 30 45 29 58. Test at 5% LOS.
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