A runner weighing 55 kg, moving at a speed of 7.2 m/s rounds a bend with a radius of 10 m. What is the centripetal force needed to keep this runner on the curve?

1 answer

To find the centripetal force needed to keep the runner on the curve, we can use the formula for centripetal force:

\[ F_c = \frac{mv^2}{r} \]

where:

  • \( F_c \) is the centripetal force,
  • \( m \) is the mass of the runner (55 kg),
  • \( v \) is the speed of the runner (7.2 m/s),
  • \( r \) is the radius of the bend (10 m).

Now, let's plug in the values:

  1. Mass, \( m = 55 \) kg
  2. Speed, \( v = 7.2 \) m/s
  3. Radius, \( r = 10 \) m

Now, substituting these values into the equation:

\[ F_c = \frac{55 , \text{kg} \times (7.2 , \text{m/s})^2}{10 , \text{m}} \]

Calculating \( (7.2 , \text{m/s})^2 \):

\[ (7.2)^2 = 51.84 , \text{m}^2/\text{s}^2 \]

Now substituting this back into the centripetal force equation:

\[ F_c = \frac{55 , \text{kg} \times 51.84 , \text{m}^2/\text{s}^2}{10 , \text{m}} \]

Calculating the numerator:

\[ 55 \times 51.84 = 2851.2 , \text{kg} \cdot \text{m}^2/\text{s}^2 \]

Now, dividing by 10 m:

\[ F_c = \frac{2851.2 , \text{kg} \cdot \text{m}^2/\text{s}^2}{10 , \text{m}} = 285.12 , \text{N} \]

Thus, the centripetal force needed to keep the runner on the curve is:

\[ \boxed{285.12 , \text{N}} \]