A runner of mass m = 58 kg and running at 2 m/s runs as shown and jumps on the rim of a playground merry-go-round which has a moment of inertia of 408 kg·m2 and a radius of 2 meters. Assuming the merry-go-round is initially at rest, what is its final angular velocity to three decimal places?

Answer 1

initial angular momentum=final ang momentum

Imgo*0+58*2^2*2/2PI2=(Imgo+58*2^2)w

where w is the final angular velocity in rad/sec. Notice 2/2pi2 is the initial angular velocity of the runners mass