A runner is jogging at a steady 3.9 km/hr.

When the runner is 7.4 km from the finish
line, a bird begins flying from the runner to
the finish line at 19.5 km/hr (5 times as fast
as the runner). When the bird reaches the
finish line, it turns around and flies back to
the runner.

After this first encounter, the bird then turns
around and flies from the runner back to the
finish line, turns around again and flies back
to the runner. The bird repeats the back and
forth trips until the runner reaches the finish
line.
How far does the bird travel from the beginning
(including the distance traveled to the
first encounter)?
Answer in units of km

1 answer

the runner and the bird travel for the same amount of time

the bird travels five times as fast as the runner, so it covers five times the distance

5 * 7.4 km = ?