A runner has four different pairs of shoes. If two shoes are selected at random, what is the probability that they will be a matching pair?
Answer: 1/7
Thanks for any help
4 answers
Do you want an explanation? It's 1 out of 7 because you took a shoe already, and need another shoe to make a pair. The odds of that second shoe matching the one you already picked is 1/7.
The number of pairs = C(8,2) = 28
the number of matching pairs = 4
prob of picking a matching pair = 4/28 = 1/7
in the answer given by "." : "The odds of that second shoe matching the one you already picked is 1/7."
They meant to say : The probability of the second shoe matching the one you already picked is 1/7.
If you wanted the odds, then
prob of match = 1/7
prob of no match = 6/7
odds in favour of a match = 1/7 : 6/7
= 1 : 6
the number of matching pairs = 4
prob of picking a matching pair = 4/28 = 1/7
in the answer given by "." : "The odds of that second shoe matching the one you already picked is 1/7."
They meant to say : The probability of the second shoe matching the one you already picked is 1/7.
If you wanted the odds, then
prob of match = 1/7
prob of no match = 6/7
odds in favour of a match = 1/7 : 6/7
= 1 : 6
2018 hsc practice question aye
I dont understand what "Reiny" means by c(2,8) what is c and why is it in an (x,y) form????
2 answers