A runner dashes from the starting line (x = 0) to a point 127 m away and then turns around and runs to a point 38 m away from the starting point in 13 seconds. To the nearest tenth of a m/s what is the average speed?

Question

What is the runner's average velocity in the previous problem?

Answer 1

average velocity = (Position at start - position at finish) which is a vector divided by time

In x direction runner goes:
38 meters

so velocity in x direction is 38/13
= 2.92 m/s in x direction