a runner completes 1/4 of a 5 mile race every 8 minutes. At the same pace, how far can he runner go in 16 minutes

Answer 1

To find out how far the runner can go in 16 minutes, we first need to determine the runner's pace and how much distance they cover in that time.

The runner completes \( \frac{1}{4} \) of a 5-mile race in 8 minutes. Let's calculate how much distance that is:

\[ \frac{1}{4} \times 5 \text{ miles} = 1.25 \text{ miles} \]

This means the runner covers 1.25 miles in 8 minutes.

Now, we will find out how much distance the runner covers in 1 minute: \[ \text{Distance per minute} = \frac{1.25 \text{ miles}}{8 \text{ minutes}} = 0.15625 \text{ miles per minute} \]

Next, we calculate how far the runner can go in 16 minutes: \[ \text{Distance in 16 minutes} = 0.15625 \text{ miles per minute} \times 16 \text{ minutes} = 2.5 \text{ miles} \]

Therefore, at the same pace, the runner can cover 2.5 miles in 16 minutes.

Answer 2

a runner completes 1/4 of a 5 mile race every 8 minutes. At the same pace, how far can he runner go in 16 minutes
160 miles
1/10 miles
1/8 miles
2 1/2 miles

Answer 3

As previously calculated, the runner completes \( \frac{1}{4} \) of a 5-mile race (which is 1.25 miles) in 8 minutes.

To find out how far the runner can go in 16 minutes:

1. Calculate the distance per minute: \[ \text{Distance per minute} = \frac{1.25 \text{ miles}}{8 \text{ minutes}} = 0.15625 \text{ miles per minute} \]

2. Calculate the distance in 16 minutes: \[ \text{Distance in 16 minutes} = 0.15625 \text{ miles per minute} \times 16 \text{ minutes} = 2.5 \text{ miles} \]

So at the same pace, the runner can cover 2.5 miles in 16 minutes.

Among the options provided, the correct answer is 2 1/2 miles.

Answer 4

water decreases 10 gallons every three hours everyday. what is the total change in the amount of water in the tank after 6 days
80 gallons
-80 gallons
-480 gallons
480 gallons

Answer 5

To find the total change in the amount of water in the tank after 6 days when it decreases by 10 gallons every 3 hours, we can follow these steps:

1. Determine the number of hours in 6 days: \[ 6 \text{ days} \times 24 \text{ hours/day} = 144 \text{ hours} \]

2. Calculate how many 3-hour intervals are in 144 hours: \[ \frac{144 \text{ hours}}{3 \text{ hours/interval}} = 48 \text{ intervals} \]

3. Calculate the total decrease in gallons: \[ 48 \text{ intervals} \times 10 \text{ gallons/interval} = 480 \text{ gallons} \]

Since the water decreases, we express the total change as negative: \[ \text{Total change} = -480 \text{ gallons} \]

Thus, the total change in the amount of water in the tank after 6 days is -480 gallons.

Answer 6

a recipe calls for 1/3 of a container of yogurt. each container of yogurt contains 150 calories. the recipe makes 4 servings. which calculation would defines this problem
1/3 times 150 divide by 4
1/3 divide by 150 divide 4
1/3 times 150 times 4
1/3 times 150 divided by 4/1
1/3

Answer 7

To solve the problem, we need to determine how many calories are in the portion of yogurt used for the recipe, and then how many calories are represented in each serving.

Steps to solve it:

1. Calculate the calories from \( \frac{1}{3} \) of a container of yogurt.
   Since the entire container of yogurt contains 150 calories:

   \[ \text{Calories in } \frac{1}{3} \text{ of the container} = \frac{1}{3} \times 150 \]

2. Calculate the calories per serving.
   Since the recipe makes 4 servings, we then divide the calories from \( \frac{1}{3} \) of the container by 4:

   \[ \text{Calories per serving} = \left(\frac{1}{3} \times 150\right) \div 4 \]

Therefore, the correct calculation that defines this problem is:

\[ \frac{1}{3} \times 150 \div 4 \]

So the answer is: 1/3 times 150 divided by 4.

Answer 8

1/2 of 1/5 of a cheese block

Answer 9

To find \( \frac{1}{2} \) of \( \frac{1}{5} \) of a cheese block, you can follow these steps:

1. Calculate \( \frac{1}{5} \) of the cheese block:
   Let's denote the entire cheese block as \( C \). So, \( \frac{1}{5} \) of the cheese block is: \[ \frac{1}{5} \times C = \frac{C}{5} \]

2. Next, calculate \( \frac{1}{2} \) of \( \frac{1}{5} \) of the cheese block: \[ \frac{1}{2} \times \left(\frac{C}{5}\right) = \frac{1}{2} \times \frac{C}{5} = \frac{C}{10} \]

So, \( \frac{1}{2} \) of \( \frac{1}{5} \) of a cheese block is \( \frac{C}{10} \) or one-tenth of the cheese block.

Answer 10

what is the ounce 1/2 of 1/5 of a cheese block

Answer 11

To determine the weight in ounces of \( \frac{1}{2} \) of \( \frac{1}{5} \) of a cheese block, we first need to know the total weight of the cheese block in ounces.

Assuming the weight of the entire cheese block is \( W \) ounces, we can start from there:

1. Calculate \( \frac{1}{5} \) of the cheese block: \[ \frac{1}{5} \times W = \frac{W}{5} \text{ ounces} \]

2. Calculate \( \frac{1}{2} \) of \( \frac{1}{5} \) of the cheese block: \[ \frac{1}{2} \times \left(\frac{W}{5}\right) = \frac{1}{2} \times \frac{W}{5} = \frac{W}{10} \text{ ounces} \]

If you know the total weight \( W \) of the cheese block, you can substitute that value into the final equation to find the weight in ounces of \( \frac{1}{2} \) of \( \frac{1}{5} \) of the cheese block.

For example, if the cheese block weighs 10 ounces: \[ \frac{1}{2} \times \frac{1}{5} \text{ of 10 ounces} = \frac{10}{10} = 1 \text{ ounce} \]

Please provide the weight of the cheese block in ounces for a specific answer, or let me know if you want me to assume a weight for an example calculation!