A runaway truck lane heads uphill at 30◦ to the horizontal.

Question

If an out of control 15000 kg truck enters the lane going at 30 m/s , how far along the ramp does it go? The acceleration due to gravity is 10 m/s2.

Answer 1

Distance = (30 m/s)^2 / (2 * 10 m/s2 * sin(30◦))
Distance = 81.65 m