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A rubber ball is thrown 20 feet into the air. If it rebounds 3/5 of the height, how far will it have traveled after the fifth bounce?

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20+20 + 12+12 + ...
40 + 24 + ...
a = 40, r=.6
Assuming that "after the 5th bounce" means "immediately the 5th bounce",
S5 = 40(1-.6^5)/(1-.6) = 92.224 ft

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