9.8=v^2/r
solve for v.
change r to meters.
A rotating cylinder about 5.0 miles in diameter is designed to be used as a space colony. With what tangential velocity must it rotate so that the residents on it will experience the same acceleration as that due to gravity on Earth? Recall that ag=g=-9.8 m/s^2 and 1 mi=1609 m.
The answer is 198 m/s....how do I get this?
I have no idea where to start.
1 answer