a rope that makes an angle of 30 degrees with the horizontal drags a crate along the floor. what must be the tension in the rope if a horizontal force of 40N is needed to drag the crate? please help me. i really didn't understand what my professor told me. he speak so fast. even in my physics book. i can't understand all of the lectures on that topic. what is the formula for it. the topic is Trigonometry and Vectors.

Answer 1

If a horizontal force of 40N is needed to pull the crate, and the rope is making 30° with the horizontal, then the horizontal component is
T(cos(30°) where T is the tension in the rope.
So
T(cos(30°))=40 N
and you can then solve for T (unit is in N).

Answer 2

thank you

Answer 3

You're welcome ! :)