A) 60 N cos 35 * 4.0 m = 196.6 J
B) 60 N cos 35 * 4.0 m - 10 N*4.0 m = ?
C) 10N*4.0m = 40 J
or (A) - (B), in terms of previous answers.
A rope that is at 35° to the horizontal is used to pull 10kg crate across a rough floor.
The crate is initially at rest and is dragged for a distance of 4.0m. The tension in the rope is 60N and the frictional force opposing the motion is 10N.
A) Calculate the work done on the crate by the tension in the rope.
B) Find the net work done on the crate.
C) Determine the energy lost from the system as heat and sound due to the frictional force.
1 answer
1 answer