First, find the Force in the y-direction.
Fy=T+Fg=ma
..or in this case
T+Fg=(mv^2)/R
Tension equals to 0 because when the pail of water is at its highest peak, there, tension does not exist.
so now we have
mg=(mv^2)/R
Cancel out mass to get...
g=(v^2)/R
(gR)^(1/2)=v
Plug in values.
A rope is tied to a pail of water and the pail is swung in a vertical circle of radius 1.3m. What must be the minimum velocity of the pail at the highest point of the circle if no water is to spill?
1 answer