A rope exerts a constant horizontal force of 203N pulling a 68-kg crate across the floor. The velocity of the crate is observed to increase from 3m/s to 5m/s in a time of 4 seconds under the influence of this force and the frictional force exerted by the floor on the crate.

Question

A rope exerts a constant horizontal force of 203N pulling a 68-kg crate across the floor. The velocity of the crate is observed to increase from 3m/s to 5m/s in a time of 4 seconds under the influence of this force and the frictional force exerted by the floor on the crate.
What is the acceleration of the crate?
What is the total force acting upon the crate?
What is the magnitude of the frictional force acting on the crate?

bobpursley · Answer

a, accekeratuin=changevelociyt/time b. net force=mass*acceleration c. net force=203-frictionforce

Anonymous · Answer

What force would have to be applied to the crate by the rope in order for the crate to move with constant velocity?