A roller coaster’s velocity at the top of a hill is 10m/s. Two seconds later it reaches the bottom of the hill with a velocity of 26m/s. What is the acceleration of the roller coaster?

Answer 1

a = ∆v/∆t = (26-10)m/s / 2s = 8 m/s^2

pretty steep hill, since falling straight down, g = 9.8 m/s^2