To calculate the kinetic energy of the car at the bottom of the hill, we can use the formula:
KE = 1/2 * m * v^2
Where:
- KE represents the kinetic energy,
- m represents the mass of the car and passengers, and
- v represents the speed of the car.
Plugging in the values given:
m = 1,088 kg
v = 33 m/s
KE = 1/2 * 1,088 kg * (33 m/s)^2
KE = 1/2 * 1,088 kg * 1,089 m^2/s^2
KE = 593,792 J
Rounded to the nearest whole number, the kinetic energy of the car at the bottom of the hill is 592,416 J.
A roller-coaster is at the top of a 62-meter hill. The car and its passengers have a total mass of 1,088 kilograms. By the time the car reaches the bottom of the hill, its speed is 74 miles per hour (33 meters per second). How much kinetic energy does the car have at the bottom of the hill?
KE=12mv2
(1 point)
Responses
592,416 J
592,416 J
17,952 J
17,952 J
2,978,944 J
2,978,944 J
1,184,832 J
1 answer