A rocket is travelling directly up at an unknown speed when it runs out of fuel at a height of 2.0km above the ground. What must its speed have been if it takes 64s to hit the ground?

Answer 1

2000 + vt - 4.9t^2 = 0
since t=64,
2000 + 64v - 4.9*64^2 = 0
v = 282.35 m/s