A rocket is launched vertically such that its acceleration upward is 4.7g. If it can maintain that acceleration, how much time (in minutes) would it take to reach the orbit of the International Space Station 310km above Earth’s surface?

Answer 1

distance = 1/2 * acceleration * time^2

working in meters ... answer in seconds
... 3.1E5 = 1/2 * 4.7 * 9.8 * t^2

find t ... divide by 60 to get minutes

Answer 2

So final answer is 0.07 minutes?

Answer 3

nooo ... more like two

3.1E5 is 310,000