measuring from the tower, if the distance away is x, and the rocket had risen to a height h when first observed,
h/x = tan25°
(h+4)/x = tan66°
Now you can solve for x.
A rocket is launched vertically into the air and is observed from a tower that is 1.5 km above the ground level. Soon after the launch the rocket is at an angle of 25 degrees. Later the rocket has climbed vertically a further 4 km and its angle of elevation from the tower is 66 degrees. How far is the observer from the launched site? Assuming that the base of the tower and the launched site is on a perfectly horizontal ground level.
1 answer
1 answer