A rocket is launched from the top of a 50 foot cliff with an initial velocity of 120 feet per second. The height, h, of the rocket after t seconds is given by the equation h=-16t^2 + 120t+ 50. How long after the rocket is launched will it be 10 feet from the ground?

Answer 1

just solve for t in

-16t^2 + 120t+ 50 = 10

probably the quadratic formula will be helpful.