H = -16(3^2) + 200(3)
H = -48 + 600
H = 552 feet
A rocket is fired upward from the ground with an initial velocity of 200 feet per second. Neglecting air resistance, the height of the rocket at any time, t, can be described in feet by the equation H=−16t^2+200t. Find the height of the rocket at t=3 seconds.
2 answers
AAAaannndd the bot gets it wrong yet again!
amazing: even with the right numbers, it blows it!
-16(3^2) + 200(3) = 456
amazing: even with the right numbers, it blows it!
-16(3^2) + 200(3) = 456