So rocket never got propulsion after launch, becomes a projectile.
u=92.0 m/s, θ=33°
horizontal velocity (constant)
ux=u cos(θ)
Time to reach wall (in seconds)
t1=26.0/ux seconds
vertical initial velocity
uy=u sin(θ)
vertical height at time t
sy(t)=uy*t-(1/2)gt^2
Substitute t=t1 to find the vertical height, and subtract 13.4 m to find clearance.
A rocket is fired at a speed of 92.0 m/s from ground level, at an angle of 33.0 ° above the horizontal. The rocket is fired toward an 13.4-m high wall, which is located 26.0 m away. The rocket attains its launch speed in a negligibly short period of time, after which its engines shut down and the rocket coasts. By how much does the rocket clear the top of the wall?
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