A rocket is fired at a speed of 75.0 m/s from ground level, at an angle of 57.3° above the horizontal. The rocket is fired toward an 11.0 m high wall, which is located 21.5 m away. By how much does the rocket clear the top of the wall?

Answer 1

u = 75 cos 57.3
so t = 21.5 /(75 cos 57.3)

Vi = 75 sin 57.3

h = Vi t - 4.9 t^2

answer = h-11