a rock is thrown vertically upward from ground level at t=0. At t= 1.5s, it passes the top of a tall tower and 1.0 s later, it reached its maximum height. what is the height of the tower?

Answer 1

Tr = 1.5 + 1 = 2.5 s. = Rise time or time to reach max ht.
V = Vo + g*Tr = 0
Vo -9.8*2.5 = 0
Vo = 24.5 m/s. = Initial velocity.

h max = Vo*t + 0.5g*t^2 =
Vo*2.5 - 4.9*2.5^2 = 2.5Vo -

Answer 2

Tr = 1.5 + 1 = 2.5 s. = Rise time or time to reach max ht.

V = Vo + g*Tr = 0
Vo -9.8*2.5 = 0
Vo = 24.5 m/s. = Initial velocity.

h = Vo*t + 0.5g*t^2 =
24.5*1.5 - 4.9*1.5^2 = 25.7 m. = Ht. of
the tower.

Answer 3

Please disregard my 5:24 PM post.