Ask a New Question

A rock is thrown upward with a velocity of 28 meters per second from the top of a 36 meter high cliff, and it misses the cliff on the way back down. When will the rock be 9 meters from the water below. Round to two decimal places.

1 answer

we have

h(t) = 36 + 28t - 4.9t^2
So, when h=9, just solve
36 + 28t - 4.9t^2 = 9
t ~= 6.55 sec

Ask a New Question or answer this question.

Similar Questions

A rock is thrown upward with a velocity of 12 meters per sec from the top of a 25 meter high cliff and it misses on it's way
1. 2 answers
If a rock is thrown upward on the planet Mars with a velocity of 17 m/s, its height (in meters) after t seconds is given by H =
1. 1 answer
on earth, in the absence of air, the rock in excersise 13 would reach a height of s=24t- 4.9t^2 meters in t seconds. How high
1. 1 answer
If a rock is thrown upward on the planet Mars with a velocity of 19 m/s, its height (in meters) after t seconds is given by H =
1. 3 answers

more similar questions