a rock is thrown straight up and reaches a height at 10 meters. 1.how long was the rock in the air 2.what is the initial vvelocity of the rock?

Question

Henry · Accepted Answer

1. V^2 == Vo + 2g*h = 0; Vo = -2g*h = 19.6*10 = 196 m/s. = Initial velocity.

V = Vo + g*Tr = 0; Tr = -Vo/g = -196/-9.8 = 20 s. = Rise time.

Tf = Tr = 20 s. Tr+Tf = 20 + 20 = 40 s. = Time in air.

2. Vo = 196 m/s(Part 1).