a. h = 0.5g*t^2
h = 20 m
g = +9,8 m/s^2
Solve for t.
b. V^2 = Vo^2 + 2g*h
Vo = 0
g = +9.8 m/s^2
h = 20 m.
Solve for V.
A rock is dropped off a 20m tall cliff. How long does it take to get to the bottom of the cliff? What is the instantaneous velocity right before it hits the bottom of the cliff?
3 answers
yes
2 seconds?
0 answers