A rock is dropped from a hotel and strikes the ground with a particular speed. In order, to double the speed at impact, you would have to drop the rock from the hotel at?
I say impossible to determine
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Yoy would have to from the rock from four times the height to get twice the velocity at impact (neglecting air friction). That is because kinetic energy in proportional to V^2. You'd need four times the kinetic energy, and that comes from four times the height (and potential energy)
1 answer