A rock falls from rest a vertical distance of 0.63 meters to the surface of a planet in 0.48 seconds. What is the magnitude of the acceleration due to gravity on that planet?

Answer 1

d = Vo*t + 0.5g*t^2 = 0.63m,
0 + 0.5g*(0.48)^2 = 0.63,
0.1152g = 0.63,
g = 5.47m/s^2.