A robot probe drops a camera off the rim of a 387 m high cliff on Mars, where the free-fall acceleration is 3.7 m/s2 .

Find the velocity with which it hits the ground.
Answer in units of m/s

2 answers

V^2 = Vo^2 + 2g*h

Vo = 0
g = 3.7 m/s^2
h = 387 m.
Solve for V
2863.8