Let the distance on the road be x. Then the distance z to the house is
z^2 = x^2+25
z dz/dt = x dx/dt
z(1) = √26
√26 dz/dt = 1 * 65
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A road perpendicular to a highway leads to a farmhouse located 5 miles away. An automobile traveling on the highway passes through this intersection at a speed of 65mph.
How fast is the distance between the automobile and the farmhouse increasing when the automobile is 1 miles past the intersection of the highway and the road?
The distance between the automobile and the farmhouse is increasing at a rate of _______ miles per hour
1 answer