a river is 60 metre wide . a tree of unknown height is one bank.the angle of elevation of the top of the tree from the point exactly opposite to the tree , on the other bank is 30°. find the height of the tree
2 answers
h/60 = tan 30°
Tan theta=P/B
Tan 30°=h/60
1/√3=h/60
60/√3=h
60√3/√3*√3=h
60√3/3=h
20*1.732=h
h=34.64 m
Tan 30°=h/60
1/√3=h/60
60/√3=h
60√3/√3*√3=h
60√3/3=h
20*1.732=h
h=34.64 m
1 answer