A rigid rod holds a restaurant sign horizontally from the side of a building. The force due to gravity acting on the sign is 165N with the angle between the sign and the rod being 50 degrees. Ignoring the weight of the rod what is the magnitude of the tension in the rod?

Answer 1

I do not know because I need to know how far from the building the center of gravity of the sign is and how far from the building the attachment point of the rod to the sign is.

Answer 2

I think
165×sin 50
=126.4 N

Answer 3

215N

Answer 4

Fy applied - Fg = 0
Fy applied (y sin theta) = Fg
Fy applied = Fg over sin theta
Fy applied = 165 over sin 50
Fy applied = 215 N