To find the length of the side opposite the 25° angle in the second right triangle, we can use the sine function, which is defined as:
\[ \sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} \]
For the second triangle, we know:
- The angle \( \theta = 25° \)
- The hypotenuse = 10
Let \( x \) be the length of the side opposite the 25° angle. We can set up the equation as follows:
\[ \sin(25°) = \frac{x}{10} \]
To solve for \( x \), we rearrange the equation:
\[ x = 10 \cdot \sin(25°) \]
Now we calculate \( \sin(25°) \). Using a calculator:
\[ \sin(25°) \approx 0.4226 \]
Therefore,
\[ x \approx 10 \cdot 0.4226 = 4.226 \]
Rounding to the nearest whole number, we find \( x \approx 4 \).
Thus, the length of the side opposite the second triangle’s 25° angle is approximately 4.
So the answer is:
The side opposite the second triangle’s 25° angle has length 4.