A right triangle has a hypotenuse of length 40 and an angle of 25°, with a side opposite this angle of length 16. A second right triangle also has an angle of 25°, with a hypotenuse of length 10. Determine the length of the side opposite the 25° angle on the second triangle.(1 point)

The side opposite the second triangle’s 25° angle has length 8.

The side opposite the second triangle’s 25° angle has length 4.

The side opposite the second triangle’s 25° angle has length 64.

The side opposite the second triangle’s 25°angle has length 8 square root 21

1 answer

To determine the length of the side opposite the 25° angle in the second triangle with a hypotenuse of length 10, we can use the sine function.

The sine of an angle in a right triangle is defined as the ratio of the length of the side opposite the angle to the length of the hypotenuse. Thus, we can express this relationship mathematically:

\[ \sin(25^\circ) = \frac{\text{opposite}}{\text{hypotenuse}} \]

For the second triangle:

  • Hypotenuse = 10
  • Opposite side (what we want to find) = \( x \)

Inserting the values, we have:

\[ \sin(25^\circ) = \frac{x}{10} \]

To find \( x \), we rearrange this equation:

\[ x = 10 \cdot \sin(25^\circ) \]

Next, we can calculate \( \sin(25^\circ) \). Using a calculator, we find:

\[ \sin(25^\circ) \approx 0.4226 \]

Now substituting this value back into the equation for \( x \):

\[ x \approx 10 \cdot 0.4226 \approx 4.226 \]

Rounding this, we find:

\[ x \approx 4 \]

Therefore, the length of the side opposite the 25° angle in the second triangle is \( \boxed{4} \).