In a right triangle with angles of 45°, the sides opposite the 45° angles are equal, and the relationship between the side lengths and the hypotenuse can be expressed using the following relation:
If the length of the side opposite the 45° angle is \( x \), then the hypotenuse \( h \) is given by:
\[ h = x \sqrt{2} \]
For the second triangle you mentioned, the side opposite the 45° angle has a length of \( 4\sqrt{2} \).
Using the formula, we can find the hypotenuse:
\[ h = (4\sqrt{2}) \sqrt{2} = 4 \cdot 2 = 8 \]
Thus, the length of the hypotenuse in the second triangle is \( 8 \).
The correct answer is: B. The hypotenuse of the second triangle has length 8.