A right rectangular pyramid has an altitude of 22.3 inches, a length of 6.75 inches, and a width of 10.25 inches. What is the volume of the pyramid in cubic inches?(1 point)

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1 answer

To find the volume of a right rectangular pyramid, you can use the formula:

\[ V = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]

Where:

  • Base Area for a rectangle = Length × Width
  • Height is the altitude of the pyramid

Given:

  • Length = 6.75 inches
  • Width = 10.25 inches
  • Height = 22.3 inches

First, calculate the base area:

\[ \text{Base Area} = 6.75 , \text{inches} \times 10.25 , \text{inches} = 69.1875 , \text{square inches} \]

Now, plug the base area and height into the volume formula:

\[ V = \frac{1}{3} \times 69.1875 , \text{inches}^2 \times 22.3 , \text{inches} \]

Calculating the volume:

\[ V = \frac{1}{3} \times 69.1875 \times 22.3 \approx \frac{1}{3} \times 1545.1875 \approx 515.0625 \]

Thus, the volume of the pyramid is approximately:

\[ \boxed{515.06} , \text{cubic inches} \]