A right pyramid on a base 4cm square has a slant edge of 6cm.calculate the volume of the pyramid

Answer 1

We need the perpendicular height of the pyramid.
Diagonal of base:
d^2 = 4^2 + 4^2 = 32
d= √32 = 4√2

then h^2 + (2√2)^2 = 6^2
h^2 = 36 - 8 = 28
h = √28

Volume = (1/3) base x height
= (1/3)(16)(√28) = (32/3)√7 cm^2 or appr. 28.22

Answer 2

First find the diagonal of the square, by using Pythagoras theorem, then divide the length of the diagonal by two cos the height of the pyramid now rest on the diagonal and it divided it into two equal parts. Now using half of the diagonal as abase and the slant edge find the height of the pyramid, when u get the height, then use the formula for volume of a pyramid and then find the volume

Answer 3

Very correct and we'll explained.
Good work

Answer 4

Good

Answer 5

How did you get 28

Answer 6

Good job
And thanks

Answer 7

I don't understand explain better

Answer 8

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