The original pyramid has a volume of (1/3) * 10^2 * 15 = 500 cubic meters.
The top 6m of the pyramid is removed, leaving a new pyramid with a height of 15-6=9 meters.
Using similar triangles, we can find that the new base of the pyramid has a side length of (4/5)*10 = 8 meters.
The volume of the new pyramid is (1/3) * 8^2 * 9 = 192 cubic meters.
Therefore, the volume of the frustrum (the remaining portion of the pyramid) is 500 - 192 = 308 cubic meters.
A right pyramid on a base 10m Square is 15m high.if the top 6m of the pyramid are removed.what is the volume of the remaining frustrum
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