The formula for the volume \( V \) of a cone is given by:
\[ V = \frac{1}{3} \pi r^2 h \]
where \( r \) is the radius of the base and \( h \) is the height of the cone.
From the problem, we have:
- The radius \( r = 5 \) cm
- The height \( h = 9 \) cm
- Using \( \pi \approx 3.14 \)
Now, we can substitute these values into the volume formula:
\[ V = \frac{1}{3} \times 3.14 \times (5^2) \times 9 \] \[ = \frac{1}{3} \times 3.14 \times 25 \times 9 \] \[ = \frac{1}{3} \times 3.14 \times 225 \] \[ = \frac{1}{3} \times 706.5 \] \[ = 235.5 \]
Rounding \( 235.5 \) to the nearest tenth gives us:
\[ \text{Volume} \approx 235.5 \text{ cubic centimeters} \]
Thus, the volume of the cone is 235.5 cubic centimeters.